-10x^2+58x=0

Solution for -10x^2+58x=0 equation:

-10x^2+58x=0

a = -10; b = 58; c = 0;
Δ = b2-4ac
Δ = 582-4·(-10)·0
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-58}{2*-10}=\frac{-116}{-20}
=5+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+58}{2*-10}=\frac{0}{-20}
=0
$